Question

Factor completely
486+108x+6x^2

Thank you!

Answer 1

Answer:

6(x + 9) (x + 9)

or

$6 (x+9)^{2}$

Step-by-step explanation:

$468 + 108x + 6x^{2} \\6x^{2} +108x + 468$

Greatest common factor of 6, 108, and 486:

6 x 1 = 6

6 x 18 = 108

6 x 81 = 486

GCF: 6

so:

$6(x^{2} +18x +81)$

$x^{2} +18x + 81$

factors to:

(x + 9) (x + 9)

because:

9 x 9 = 81

9 + 9 = 18

So:

It factors completely too:

6(x + 9) (x + 9)

or

$6 (x+9)^{2}$