Respuesta :

Answer:

[tex]Jane = 15\frac{3}{10}[/tex]

Step-by-step explanation:

Given

[tex]Kent = 12\frac{4}{5}[/tex]

[tex]Lane = 1\frac{1}{6} + Kent[/tex]

[tex]Jane = 1\frac{1}{3} + Lane[/tex]

Required

Determine Jane's age

Substitute [tex]Kent = 12\frac{4}{5}[/tex] in [tex]Lane = 1\frac{1}{6} + Kent[/tex]

[tex]Lane = 1\frac{1}{6} + 12\frac{4}{5}[/tex]

[tex]Lane = \frac{7}{6} + \frac{64}{5}[/tex]

Take LCM

[tex]Lane = \frac{45+384}{30}[/tex]

[tex]Lane = \frac{419}{30}[/tex]

Substitute [tex]Lane = \frac{419}{30}[/tex] in [tex]Jane = 1\frac{1}{3} + Lane[/tex]

[tex]Jane = 1\frac{1}{3} + \frac{419}{30}[/tex]

[tex]Jane = \frac{4}{3} + \frac{419}{30}[/tex]

Take LCM

[tex]Jane = \frac{40+419}{30}[/tex]

[tex]Jane = \frac{459}{30}[/tex]

[tex]Jane = 15\frac{3}{10}[/tex]