Question

A mix of factoring by grouping. Factor the exressions. 17ax+17a-x-1 Please explain/show steps on how to do this!

Answer 1

Answer:

$(17a-1)(x+1)$

Step-by-step explanation:

Given: Expression is $17ax+17a-x-1$

To factor: the given expression

Solution:

Take $17a$ common from the first two terms and $-1$ from the last two terms.

$17ax+17a=17a(x+1)$

and

$-x-1=-(x+1)$

So,

$17ax+17a-x-1=17a(x+1)-1(x+1)\\=(17a-1)(x+1)$

Therefore,

$17ax+17a-x-1=(17a-1)(x+1)$