Answer:
2.232 g/L
Explanation:
Assuming 1 mol, volume at STP is 22.4 L so you simply divide 50g by 22.4 L to get density
The density of the given gas is required.
The density of the gas at STP is 2.232 g/L.
M = Molar mass of gas = 50 g/mol
1 mole of any gas at STP occupies 22.4 L.
V = Volume per mole = 22.4 L/mol
Density is given by
[tex]\rho=\dfrac{M}{V}\\\Rightarrow \rho=\dfrac{50}{22.4}\\\Rightarrow \rho=2.232\ \text{g/L}[/tex]
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