Given:
The points are A(3, -3), B(-3, -2), C(-5, 1), D(-5, 4), E(-4 ,6), F(-2, 6), G(3, 2).
To find:
The length of EF and plot each point on a coordinate plane and connect them.
Solution:
Plot the given point A(3, -3), B(-3, -2), C(-5, 1), D(-5, 4), E(-4 ,6), F(-2, 6), G(3, 2) on coordinate plane and connect them as shown in the below figure.
From the below graph it is clear that the length of EF is 2 units. We can verify this solution by using the distance formula.
Distance formula:
[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using the distance formula, the distance between E(-4 ,6) and F(-2, 6) is
[tex]D=\sqrt{(-2-(-4))^2+(6-6)^2}[/tex]
[tex]D=\sqrt{(-2+4)^2+(0)^2}[/tex]
[tex]D=\sqrt{(2)^2+0}[/tex]
[tex]D=2[/tex]
Therefore, the length of EF is 2 units.
