The graph of h is the graph of f(x) = x2 translated 2 units left and 5 units up. What is the vertex form of this function?
A. h(x) = (x + 2)2 + 5
B. h(x) = (x - 2)2 + 5
C. h(x) = (x + 5)2 + 2
D. h(x) = (x + 5)2 - 2

The graph of h is the graph of fx x2 translated 2 units left and 5 units up What is the vertex form of this function A hx x 22 5 B hx x 22 5 C hx x 52 2 D hx x class=

Respuesta :

Answer:

A. [tex]h(x) = (x+2)^{2}+5[/tex]

Step-by-step explanation:

First, we need to defined the two transformations required to derive [tex]h(x)[/tex].

Vertical translation

[tex]n(x) = m(x) +k[/tex], [tex]k \in \mathbb{R}[/tex] (1)

Where:

[tex]k > 0[/tex], upwards.

[tex]k < 0[/tex], downwards.

Horizontal translation

[tex]n(x) = g(x+k)[/tex], [tex]k\in \mathbb{R}[/tex] (2)

Where:

[tex]k > 0[/tex], leftwards.

[tex]k < 0[/tex], rightwards.

Let [tex]f(x) = x^{2}[/tex], if [tex]h(x)[/tex] is translated 2 units left and 5 units up, then we have the resulting expression:

[tex]h(x) = (x+2)^{2}+5[/tex] (3)

Hence, correct answer is A.

ACCESS MORE