Answer:
The correct solution is "21024 KWh/degree day".
Explanation:
The given query is incomplete. Below is the attachment of complete query is provided.
The given values are:
Indoor design temperature:
= 70°F
Now,
According to the question,
The heat loss annually will be:
= [tex]12\times 24\times 365[/tex]
= [tex]105120 \ KW[/tex]
Degree days will be:
= [tex]75-65[/tex]
= [tex]5[/tex]
Hence,
Annual KWh use will be:
= [tex]\frac{Heat \ loss \ annually}{degree \ days}[/tex]
On substituting the values, we get
= [tex]\frac{105120}{5}[/tex]
= [tex]21024 \ KWh/degree \ day[/tex]
