Answer:
4.95 mL
Step-by-step explanation:
Since we have 400 mg/m² of gemcitabine for a patient whose BSA is 0.47 m², the mass of drug required for the patient is thus m = 400 mg/m² × 0.47 m² = 188 mg.
Also, since 200 mg vial of gemcitabine for injection that contains 38 mg per mL, so the concentration of gemcitabine is 38 mg/mL.
Since concentration = mass/volume, and
volume = mass/concentration,
the volume of gemcitabine injection required is
V = mass of gemcitabine/concentration of gemcitabine in injection
V = 188 mg/38 mg/mL
V = 4.95 mL