Answer:
sin2θ = [tex]\frac{12}{13}[/tex]
Step-by-step explanation:
Since, sin2θ = 2sinθcosθ
From the triangle given in the picture,
Opposite side of angle θ = 2 units
Adjacent side of angle θ = 3 units
Hypotenuse = [tex]\sqrt{2^2+3^2}[/tex] = [tex]\sqrt{13}[/tex] [By Pythagoras theorem]
sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{2}{\sqrt{13}}[/tex]
cosθ = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{3}{\sqrt{13} }[/tex]
sin2θ = [tex]2\times (\frac{2}{\sqrt{13}})(\frac{3}{\sqrt{13}})[/tex]
= [tex]\frac{12}{13}[/tex]
