Question

Which is the equation for the line that has a slope of 12 and passes through the point (3, 20)?

y = 12x - 16

y = 12x + 16

y = 16x - 12

y = 16x + 12

Answer 1

Answer:

the first one

Step-by-step explanation:

y-y1=m(x-x1)

y-20=12(x-3)

$y-20+20=12\left(x-3\right)+20$

simplify:

$y=12x-16$