Answer:
Step-by-step explanation:
We will prove the converse of the postulate,
"If a line parallel to one side of a triangle and it intersects other two sides of the triangle, then the line will divide both the sides in the same ratio"
Segment DE intersects AB and BC at D and E respectively,
Ratio of the segments of two sides,
[tex]\frac{AD}{DB}=\frac{CE}{EB}[/tex]
[tex]\frac{22.5}{15}=\frac{24}{40-24}[/tex]
1.5 = 1.5
True.
Therefore, lines AC and DE are parallel.
