Question

3. A sample of air in a syringe exerts a pressure of 1.02 atm at 22.0°C. The syringe is placed in a boiling-water bath at 100.0°C. The
pressure is increased to 1.23 atm by pushing the plunger in, which reduces the volume to 0.224ml What was the initial volume?

Answer 1

Answer:

0.214 mL    

explanation:

Answer 2

Ideal Gas law is applied to the ideal gases. The initial volume of air in the syringe when applied pressure and reducing the volume to 0.2234 mL is 0.214 mL.

What is the Ideal Gas Equation ?

The equation relating all the characteristics of a gas and behaving or assuming to be ideal is the ideal gas law equation.

pV = nRT

Here, p is the pressure, V is the volume, R is the universal gas constant, n is the number of moles and T is the temperature.

According to the law, the initial and final values of gas are related as

$\dfrac{P_{1} V_{1} }{T_{1} } =\dfrac{P_{2} V_{2} }{T_{2} }$

The initial pressure P₁ is 1.02 atm and final pressure P₂ is 1.23 atm.

The  initial temperature T₁  is (22+273)=295 K and the final temperature (100+273)=373 K

The final volume  V₂ given is 0.224 mL

Placing the values into the ideal gas equation and solving, we get the value of initial volume.

V₁= 0.214 mL

The initial volume of air in the syringe when applied  pressure and   reducing the volume to 0.2234 mL is 0.224 mL.

Learn more about Ideal gas law equation.

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