Question

The points (1, 4) and (−3, 2) are the endpoints of a diameter of a circle. What is the equation of the circle?

Answer 1

Answer:

Step by step

Step-by-step explanation:

Since we have the endpoints of the diameter, the midpoint coordinates of the line segment joining them gives the centre of the circle.

That is, centre (a,b) = ( [1+(-3)]/2, [4+2]/2) = (-1,3)

Distance between the given points give the diameter and half of that is the radius length.

So, radius r = (1/2)* sqrt ( [1-(-3)]^2 + [4–2]^2) = sqrt(5)

Thus equation required is: (x-a)^2 + (y-b)^2 = r^2

So, (x+1)^2 + (y-3)^2 = 5

Answer 2

The equation of the circle is (x + 1)² + (y - 3)² = 5

How to determine the circle equation?

The endpoints of the diameter are given as:

(1, 4) and (−3, 2)

Start by calculating the midpoint using:

Midpoint = 0.5 * (x₁ + x₂, y₁ + y₂)

So, we have:

Midpoint = 0.5 * (1 - 3, 4 + 2)

Evaluate

Midpoint = (-1, 3)

So, the center (a,b) of the circle is:

(a,b) = (-1,3)

Calculate the length of the diameter using:

D² =(x₁ - x₂)² + (y₁ - y₂)²

This gives

D² = (1 + 3)² + (4 - 2)²

D² = 20

Take the square roots

D = 2√5

Divide by 2 to calculate the radius

r = √5

Square both sides

r² = 5

The equation of the circle is then represented as:

(x - a)² + (y - b)² = r²

This gives

(x + 1)² + (y - 3)² = 5

Hence, the equation of the circle is (x + 1)² + (y - 3)² = 5

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