Question

how many mols of K+ ions in 1.75 mol of K2SO4

Answer 1

Answer:

$3.5 mol K^+$

Explanation:

Hello there!

In this case, since the mole-mole rations consider the amount of the specific ion in the whole compound, we can evidence that the potassium sulfate has two potassium ions in the molecule; in other words, there is a 1:2 mole ratio of the former to the latter; in such a way, we can perform the following proportional factor:

$1.75molK_2SO_4*\frac{2molK^+}{1molK_2SO_4}$

So we cancel out moles of potassium sulfate to obtain:

$3.5 mol K^+$

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