Question

I have an unknown quantity of gas in 31.0 L at 260 mmHg and 87°C, how many moles of gas do I have
A 1.48 moles
B 0.36 moles
C 22.4 moles
D. 273 moles

Answer 1

Answer: B. 0.36 moles

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 260 mm Hg = 0.342 atm         (760 mm Hg= 1atm)

V = Volume of gas = 31.0 L

n = number of moles = ?

R = gas constant =$0.0821Latm/Kmol$

T =temperature =$87^0C=(87+273)K=360K$

$n=\frac{PV}{RT}$

$n=\frac{0.342atm\times 31.0L}{0.0821L atm/K mol\times 360K}=0.36moles$

Thus the moles of gas present are 0.36