Respuesta :

Answer:

113.80 mL

Explanation:

Given that:

Volume [tex]V_1 = 140 mL[/tex]

Temperature [tex]T_1 = 35.0^0C[/tex]

[tex]= (273 + 35) = 308 \ K[/tex]

Pressure [tex]P_1 = 697 mmHg[/tex]

At standard temperature and pressure;

Temperature [tex]T_2 = 273 K[/tex]

Pressure[tex]P_2[/tex] = 760 mmHg

Using the formula for a combined gas law:

[tex]\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2}[/tex]

[tex]V_2 = \dfrac{P_1V_1T_2}{T_1P_2}[/tex]

[tex]V_2 = \dfrac{697 \ mmHg \times 140 \ mL \times 273 \ K }{308 \ K \times 760 \ mmHg}[/tex]

[tex]\mathbf{V_2 = 113.80 \ mL}[/tex]

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