Question

Can someone help?

Solve the following equation for all values of x. Be sure to check for extraneous roots.

Answer 1

Answer:

$x=2$

Step-by-step explanation:

First, let's multiply both sides by $\sqrt{x+11}$. If we do this, we would have:

$x-1=\frac{1}{\sqrt{x+11}}\cdot\sqrt{x+11}$

The $\sqrt{x+11}$ would cancel out and we would be left with:

$x-1=1$

If we add 1 on both sides, we would get:

$x=2$

Hope this helps!!!