Answer:
600
Step-by-step explanation:
Consider ABC and ACD as two triangles. And AC as a base to both of them
so,
AC = AO + OC
= 15 + 25
= 40
Now the area of ABC =
[tex]\frac{1}{2}\times AC\times OB\\= \frac{1}{2}\times 40 \times 10\\= 200[/tex]
In the same way, the area of ACD =
[tex]\frac{1}{2}\times AC\times OD\\= \frac{1}{2}\times 40 \times 20\\= 400[/tex]
Both added together 400 + 200 = 600
