Question

A and b are positive integers and a-b=2 ... Evaluate the following:
27^1/3 b / 9^1/2 a
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Answer 1

Answer:

Step-by-step explanation:

a-b=2

$\frac{27^{\frac{1}{3} b} }{9^{\frac{1}{2}a } } \\=\frac{(3^{3}) ^{\frac{1}{3} b} }{(3^{2} )^{\frac{1}{2} a} } \\=\frac{3^b}{3^a} \\=3^{b-a} \\=3^{-(-b+a)} \\=3^{-2}\\=\frac{1}{3^2} \\=\frac{1}{9}$