Question

What is the net force acting on a 52 kg object that has a velocity of 8.0 m/s and is moving in a circle of radius 1.6 m? a. 4000N b. 20880N c. 2500N d. 3500N

Answer 1

Σf = m a
Σf = m v^2 / r
Σf = 52 8^2 / 1.6
Σf = 2080 N

Answer 2

The net force acting of the object will be "2080 N".

Given values are:

• Mass, m = 52 kg
• Velocity, v = 8.0 m/s
• Radius, r = 1.6 m

As we know the formula,

→ $\Sigma f = ma$

or,

→ $\Sigma f = \frac{mv^2}{r}$

By putting the values, we get

         $= \frac{52\times 8^2}{1.6}$

         $= \frac{52\times 64}{1.6}$

         $= 2080 \ N$

Thus the response above is appropriate.

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