Points B,C and D lie on a straight line. AC is perpendicular to BD. BC=6cm and BD=22cm. Triangle ABC has area 42cm^2. Calculate the size of angle x

Answer:
41.18
Step-by-step explanation:
CD=22-6=16
42=1/2×6×AC
AC=14
tanθ=O/A
tanθ=(14/16)
x=tan-1(14/16)
x=41.18
The measure of the angle x in the right triangle ABD is 41.2 degrees.
A right angle triangle has one of its angles as 90 degrees. Therefore, the sides of the triangle can be found using trigonometric ratios.
area of a triangle = 1 / 2 bh
where
Hence,
area of a triangle = 1 / 2 × 6 × h
42 = 3h
h = 42 / 3
h = 14 cm
DC = 22 - 6 = 16 cm
AC = 14 cm
tan x = opposite / adjacent
tan x = 14 / 16
x = tan ⁻¹ 0.875
x = 41.1859251657
x = 41.2 degrees.
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