Respuesta :

Answer:

[tex]11.18\ \text{units}[/tex]

[tex]10.3^{\circ}[/tex]

Step-by-step explanation:

[tex]w=<-6,-5>[/tex]

[tex]z=<5,-3>[/tex]

z is subtracted from w so

[tex]w-z=<-6-5,-5-(-3)>\\\Rightarrow w-z=<-11,-2>[/tex]

Magnitude is given by

[tex]\sqrt{(-11)^2+(-2)^2}=5\sqrt{5}=11.18[/tex]

The magnitude of the resulting vector is approximately [tex]11.18\ \text{units}[/tex].

The angle is

[tex]\theta=\tan^{-1}\dfrac{-2}{-11}\\\Rightarrow \theta=10.3^{\circ}[/tex]

The direction is approximately [tex]10.3^{\circ}[/tex]

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