Respuesta :
an easy way to do this is by using the simplest equations you can:
x + y and x - y
(3, 5) is (x, y). all you have to do is plug those into your equations and get a result, so:
x + y = 8
(because 3 + 5 = 8)
x - y = -2
(because 3 - 5 = -2)
and those can serve as your system of equations.
you can check it by solving by substitution:
x - y = -2
x + y = 8
solve one of the equations for a single variable:
x = y - 2
plug it into the second equation:
(y - 2) + y = 8
y - 2 + y = 8
2y - 2 = 8
2y = 10
y = 5
then plug that result back into the equation:
x + y = 8
x + 5 = 8
x = 3
x + y and x - y
(3, 5) is (x, y). all you have to do is plug those into your equations and get a result, so:
x + y = 8
(because 3 + 5 = 8)
x - y = -2
(because 3 - 5 = -2)
and those can serve as your system of equations.
you can check it by solving by substitution:
x - y = -2
x + y = 8
solve one of the equations for a single variable:
x = y - 2
plug it into the second equation:
(y - 2) + y = 8
y - 2 + y = 8
2y - 2 = 8
2y = 10
y = 5
then plug that result back into the equation:
x + y = 8
x + 5 = 8
x = 3
The system of equations that will give the solution (5, 3) are x+y = 8 and y-x = 3
We are to create a system of equations that has a pair of solutions (3, 5)
Let the coordinate of the unknown be expressed as (x, y)
we can take the sum of the variables to have:
x + y = 8 (Since 5 +3 is 8)
Taking the difference of the variables
y - x = 3
Hence the system of equations that will give the solution (5, 3) are x+y = 8 and y-x = 3
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