Answer:
t = 6.63 s
Explanation:
Given that,
Initial velocity of the puck, u = 7.3 m/s
Deacceleration of the puck, a = -1.1 m/s²
Distance traveled, d = 5 m
We need to find the time the goalie have to stop the puck. Using equation of motion.
v = u +at
v = 0 (stops)
So,
[tex]u=-at\\\\t=\dfrac{u}{-a}\\\\t=\dfrac{7.3}{-(-1.1)}\\\\t=6.63\ s[/tex]
So, the required time is 6.63 seconds.