Question

3. En un centro cultural, el 60% estudia música, el 45% estudia pintura y un 10% estudia ambas disciplinas. Sabiendo que un alumno escogido al azar estudia pintura, ¿cuál es la probabilidad de que también estudie música?

Answer 1

Answer:

The answer is below

Explanation:

Sea M los que estudian música, P los que estudian pintura.

Por lo tanto, P(M) = 60% = 0.6, P(P) = 45% = 0.45, P (M ∩ P) = 10% = 0.1

Sabiendo que un estudiante elegido al azar estudia pintura, la probabilidad de que también estudie música = probabilidad de que el estudiante estudie música dado que estudia pintura = P (M \ P)

P (M \ P) = P (M ∩ P) / P(P) = 0.1 / 0.45 = 0.22

Answer 2

The probability that he also studies music is 2/9

From the given information;

• Let M represent those who study music
• Let P represent those who study painting.
• Let MnP represent those who study both;

If a randomly chosen student studies painting, the probability that he also studies music is equal to the probability that the student studies music given that he studies painting.

Since this is a conditional probability, hence;

• Pr(M\P) = P(MnP)/P(P)
• Pr(M\P) = 10/45
• Pr(M\P) = 2/9

Hence the probability that he also studies music is 2/9

Learn more on conditional probability here: https://brainly.com/question/10739997