Which condition would prove ΔDEF ∼ ΔJKL?

The condition that proves congruent of two given triangles ΔDEF ∼ ΔJKL would be option A; DE : JK.
Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.
we have given proof two triangles congruent by the postulate of SSS.
Since two corresponding sides of these triangles are congruent so additional third side should also be congruent to prove both the triangles congruent.
AC ≅ DF will complete the SSS property to prove both the triangles are congruent.
DE : JK
= 21 : 7
= 3 : 1
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