Respuesta :

Answer:

Step-by-step explanation:

[tex]\frac{a^{m}}{a^{n}}=a^{m-n}\\\\a^{-m}=\frac{1}{a^{m}}\\\\\\\frac{x^{2}y^{-3}}{x^{5}y^{2}}=x^{(2-5)}*y^{(-3-2)}\\\\ = x^{-3}*y^{-5}\\\\=\frac{1}{x^{3}y^{5}}[/tex]

Remember that exponents (or powers) of the same basis can be divided by subtracting the exponents. For example [tex]\frac{x^n}{x^m} =x^{n-m}[/tex]

Using this information, we can easily rearrange our equation to look like this:

[tex]\frac{x^2}{x^5} \frac{y^{-3}}{y^2}[/tex]

Now that the basis are the same, we can conveniently subtract the exponents to get the following result:

[tex]x^{-3}y^{-5}[/tex] or [tex]\frac{1}{x^3y^5}[/tex]. And that's the final answer.

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