Question

An oil with density 900 kg/m3 and kinematic viscosity 0.0002 m2/s flows upward through an inclined pipe as shown in figure below. The pressure and elevation are known at sections 1 and 2, 10 m apart. Assuming steady laminar flow

Answer 1

Answer:

P=900KG/M3

U=0.0002 M2/S

RE=PV/U

=900*10/0.0002

=45000000

Explanation:

Answer 2

The Reynold number will be 4.5×10⁷. Reynold's number is found as the ratio of the inertial to the viscous force.

What is density?

Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.

The mass and density relation is given as

mass = density × volume

The ratio of inertial to viscous force is known as Reynold's number.

$\rm R_E= \frac{\rho u L}{\mu} \\\\ \rm R_E=\frac{900 \times 10}{0.0002} \\\\ R_E=45000000$

Hence, the Reynold number will be 4.5×10⁷.

To learn more about the density refers to the link;

brainly.com/question/952755

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