What is the area of the segment?

Answer:
28.54 ft²
Step-by-step explanation:
Area of segment = [tex] (\frac{\theta * \pi}{360} - \frac{sin(\theta)}{2}) * r^2 [/tex]
Where,
[tex] \theta = 90 [/tex]
r = 10 ft
Plug in the values
[tex] (\frac{90 * \pi}{360} - \frac{sin(90)}{2}) * 10^2 [/tex]
[tex] (0.7854 - 0.5) * 100 [/tex]
[tex] (0.2854) * 100 [/tex]
= 28.54 ft²