Question

The bolts on the cylinder head of an engine require tightening to a torque of 95 mN. If a wrench is 28 cm long, what force perpendicular to the wrench must the mechanic exert at its end

Answer 1

Answer:

339.29 N

Explanation:

From the question,

Torque = Force×Radius

τ = F×r................. Equation 1

Where

τ = torque, F = Force, r = radius of length of the Wrench.

make F the subject of the equation

F = τ/r.................. Equation 2

Given: τ = 95 Nm, r = 28 cm = 0.28 m

Substitute these values into equation 2

F = 95/0.28

F = 339.29 N

Hence the force perpendicular to the wrench is 339.29 N