Respuesta :

Answer:

[tex]n = \frac{4}{3}c[/tex]

[tex]c:0\ \ \ \frac{3}{4}\ \ \ \frac{3}{2}\ \ \ \frac{9}{4}\ \ \ 3\ \ \ 3\frac{3}{4}\\n:0\ \ \ \ 1\ \ \ 2\ \ \ 3\ \ \ \ 4\ \ \ \ 5[/tex]

Step-by-step explanation:

Given

See attachment for complete question

Required

Complete the double number line

The given double number lines represent a linear function between cups of flour (c) and number of batched (n)

Pick any two pairs:

[tex](c_1,n_1) = (\frac{3}{4},1)[/tex]

[tex](c_2,n_2) = (3\frac{3}{4},5)[/tex]

First, calculate the rate of change (i.e. slope, m):

[tex]m = \frac{n_2 - n_1}{c_2 - c_1}[/tex]

[tex]m = \frac{5-1}{3\frac{3}{4} - \frac{3}{4}}[/tex]

[tex]m = \frac{4}{3}[/tex]

So: the equation is:

[tex]n = m(c - c_1) + n_1[/tex]

This gives:

[tex]n = \frac{4}{3}(c - \frac{3}{4}) + 1[/tex]

[tex]n = \frac{4}{3}c - 1 + 1[/tex]

[tex]n = \frac{4}{3}c[/tex]

So, the above represents the relationship between n and c.

To complete the table

When [tex]n = 2[/tex]

Substitute [tex]n = 2[/tex] in: [tex]n = \frac{4}{3}c[/tex]

[tex]2 = \frac{4}{3}c[/tex]

Make c the subject

[tex]c = \frac{3*2}{4}[/tex]

[tex]c = \frac{3}{2}[/tex]

When [tex]n = 3[/tex]

Substitute [tex]n = 3[/tex] in: [tex]n = \frac{4}{3}c[/tex]

[tex]3 = \frac{4}{3} * c[/tex]

Make c the subject

[tex]c = \frac{3*3}{4}[/tex]

[tex]c = \frac{9}{4}[/tex]

When [tex]c=3[/tex]

Substitute [tex]c=3[/tex] in: [tex]n = \frac{4}{3}c[/tex]

[tex]n = \frac{4}{3} * 3[/tex]

[tex]n = 4[/tex]

So, the complete table is:

[tex]c:0\ \ \ \frac{3}{4}\ \ \ \frac{3}{2}\ \ \ \frac{9}{4}\ \ \ 3\ \ \ 3\frac{3}{4}\\n:0\ \ \ \ 1\ \ \ 2\ \ \ 3\ \ \ \ 4\ \ \ \ 5[/tex]

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