Respuesta :
Answer:
[tex]n = \frac{4}{3}c[/tex]
[tex]c:0\ \ \ \frac{3}{4}\ \ \ \frac{3}{2}\ \ \ \frac{9}{4}\ \ \ 3\ \ \ 3\frac{3}{4}\\n:0\ \ \ \ 1\ \ \ 2\ \ \ 3\ \ \ \ 4\ \ \ \ 5[/tex]
Step-by-step explanation:
Given
See attachment for complete question
Required
Complete the double number line
The given double number lines represent a linear function between cups of flour (c) and number of batched (n)
Pick any two pairs:
[tex](c_1,n_1) = (\frac{3}{4},1)[/tex]
[tex](c_2,n_2) = (3\frac{3}{4},5)[/tex]
First, calculate the rate of change (i.e. slope, m):
[tex]m = \frac{n_2 - n_1}{c_2 - c_1}[/tex]
[tex]m = \frac{5-1}{3\frac{3}{4} - \frac{3}{4}}[/tex]
[tex]m = \frac{4}{3}[/tex]
So: the equation is:
[tex]n = m(c - c_1) + n_1[/tex]
This gives:
[tex]n = \frac{4}{3}(c - \frac{3}{4}) + 1[/tex]
[tex]n = \frac{4}{3}c - 1 + 1[/tex]
[tex]n = \frac{4}{3}c[/tex]
So, the above represents the relationship between n and c.
To complete the table
When [tex]n = 2[/tex]
Substitute [tex]n = 2[/tex] in: [tex]n = \frac{4}{3}c[/tex]
[tex]2 = \frac{4}{3}c[/tex]
Make c the subject
[tex]c = \frac{3*2}{4}[/tex]
[tex]c = \frac{3}{2}[/tex]
When [tex]n = 3[/tex]
Substitute [tex]n = 3[/tex] in: [tex]n = \frac{4}{3}c[/tex]
[tex]3 = \frac{4}{3} * c[/tex]
Make c the subject
[tex]c = \frac{3*3}{4}[/tex]
[tex]c = \frac{9}{4}[/tex]
When [tex]c=3[/tex]
Substitute [tex]c=3[/tex] in: [tex]n = \frac{4}{3}c[/tex]
[tex]n = \frac{4}{3} * 3[/tex]
[tex]n = 4[/tex]
So, the complete table is:
[tex]c:0\ \ \ \frac{3}{4}\ \ \ \frac{3}{2}\ \ \ \frac{9}{4}\ \ \ 3\ \ \ 3\frac{3}{4}\\n:0\ \ \ \ 1\ \ \ 2\ \ \ 3\ \ \ \ 4\ \ \ \ 5[/tex]
