Answer:
[tex]z = -0.8[/tex]
Step-by-step explanation:
Given
[tex]n = 32[/tex] --- samples
[tex]\mu = 18g[/tex] --- mean
[tex]\sigma =5g[/tex] --- standard deviation
[tex]x = 14g[/tex] --- observed value
Required
Find the standardized score
This is calculated as:
[tex]z = \frac{x - \mu}{\sigma}[/tex]
So:
[tex]z = \frac{14g -18g}{5g}[/tex]
[tex]z = \frac{-4g}{5g}[/tex]
[tex]z = \frac{-4}{5}[/tex]
[tex]z = -0.8[/tex]
The standardized score is -0.8