Respuesta :
If the rectangular field has notional sides X and y then it has area
A(x) =xy { =6•10^6 sq ft }
The length of fencing required, if
x
is the letter that was arbitrarily assigned to the side to which the dividing fence runs parallel, is:l (x) = 3x +2y
It matters not that the farmer wishes to divide the area into 2 exact smaller areas.
Assuming the cost of the fencing is proportional to the length of fencing required, then
C(x)=a L (x)
To optimise cost, using the Lagrange Multiplier
λ
, with the area constraint :
So the farmer minimises the cost by fencing-off in the ratio 2:3, either-way

The relationship between variable F and x is 2x + 12000000/x
Let y represent the length (in feet) of a side perpendicular to the dividing fence, and let x represent the length (in feet) of a side parallel to the dividing fence.
Let F represent the length of fencing in feet.
Area of fencing = 6000000 ft²
Area of fencing = x * (y + y) = x * 2y
Area of fencing = 2xy
6000000=2xy
xy = 3000000
y = 3000000/x
The perimeter is:
F = x + y + y + x + y + y
F = 2x + 4y
F = 2x + 4(3000000/x)
F = 2x + 12000000/x
Therefore the relationship between variable F and x is 2x + 12000000/x
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