Question

Can someone help me please


A 70.0 g piece of metal wire is heated, and the temperature of the wire changes from 58.0°C to 152.0°C. The amount of heat absorbed is 972 Joules. What is the specific heat of the metal wire?


a 0.148 J/gC

b 6.77 J/gC

c 724 J/gC

d 0.0913 J/gC

Answer 1

Answer:

$c=0.1477\ J/g^{\circ} C$

Explanation:

Given that,

Mass, m = 70 g

The temperature of the wire changes from 58.0°C to 152.0°C.

Heat absorbed, Q = 972 J

We need to find the specific heat of the metal wire. The heat absorbed is given by :

$Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{972\ J}{70\ g \times (152-58)^{\circ} C}\\\\c=0.1477\ J/g^{\circ} C$

or

$c=0.148\ J/g^{\circ} C$

So, the correct option is (a).