Question

Consider the redox reaction below. Upper M g (s) plus Pper f e superscript 2 plus (a q) right arrow upper M g superscript 2 plus (a q) plus upper F e (s). Which equation is a half reaction that describes the reduction that is taking place?

Answer 1

Answer: $Fe^{2+}(aq)+2e^-\rightarrow Fe(s)$

Explanation:

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

 Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

$Mg(s)+Fe^{2+}(aq)\rightarrow Fe(s)+Mg^{2+}(aq)$

The oxidation half reaction is:

$Mg(s)\rightarrow Mg^{2+}(aq)+2e^-$

The reduction half reaction is:

$Fe^{2+}(aq)+2e^-\rightarrow Fe(s)$

Answer 2

Answer:

A

Explanation:

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