Answer:
3x^2-4x+12
Step-by-step explanation:
x(2x+3)+(x-3)(x-4)
2x^2+3x+x^2-3x-4x+12
2x^2+x^2+3x-3x-4x+12
3x² -4x + 12
x(2x + 3) + (x - 3)(x - 4)
= 2x² + 3x + x² - 4x -3x + 12
= 3x² -4x + 12
