Answer:
[tex]\$2091.3[/tex]
Step-by-step explanation:
Let P denotes initial value of the product, r% is the annual depreciation rate and t denotes time period.
Depreciation (d) = [tex]P(1-\frac{r}{100})^t[/tex]
Put [tex]P=\$2,600,\,r\%=7\%,\,t=3[/tex] years
Therefore,
[tex]d=P(1-\frac{r}{100})^t\\\\=2600(1-\frac{7}{100})^3 \\\\=2600(\frac{93}{100})^3\\\\=\$2091.3[/tex]