Question

10 moles of potassium hydroxide in 5.16 L of solution

Answer 1

Answer:

The molarity is 8.52M

Explanation:

molality = moles of solute/kg of solvent = 5.2mol/kg

moles of solute = 5.2mole

mass of solute = moles of solute × MW = 5.2 × 56.106 = 291.8g

mass of solvent = 1kg = 1000g

Mass of solution = mass of solute + mass of solvent = 291.8g + 1000g = 1291.8g

Density of KOH = 2120g/L

Volume of solution = mass/density = 1291.8/2120 = 0.61L

Molarity = number of moles of solute/volume of solution = 5.2/0.61 = 8.52M

Answer 2

The concentration in the solution is 1.94 mol/L

From the question,

We are to determine the concentration of 10 moles of potassium hydroxide in 5.16 L of solution.

From the formula

Number of moles = Concentration × Volume

Then, we can write that

$Concentration = \frac{Number\ of\ moles}{Volume}$

From the question,

Number of moles of potassium hydroxide (KOH) = 10 moles

Volume of solution = 5.16 L

∴ Concentration of the solution = $\frac{10}{5.16}$

Concentration of the solution = 1.94 mol/L

Hence, the concentration in the solution is 1.94 mol/L

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Here is the complete question:

Calculate the concentration in each of the following solutions:

1. 10 moles of potassium hydroxide in 5.16 L of solution