Help ASAP I’ll mark you as brainlister

Answer:
Step-by-step explanation:
1. I can't see the first one very well.
2. Find the area of each triangle by doing 1/2 * base * height. This should give you [tex]40m^{2}[/tex]
3. The area of a trapezium is [tex]\frac{1}{2} (a+b)h[/tex] where a is the top edge, b is the bottom edge and h is the height.
We can work out the bottom edge using pythagoras - split the trapezium into 2 triangles on each side and a rectangle in the middle. This gives you the length of the bottom edge which is 2 + 2 + 2 = 6'
Work out the area by doing 1/2(2+6)4 = 16' squared.
4.Split this shape into a triangle and rectangle. We know the right hand edge of the triangle= 9-4 = 5'.
To find the bottom edge of the triangle, use tanθ=opposite/adjacent line. Therefore tan45=bottom edge of triangle/5'. tan 45=1 therefore bottom edge = 5'.
The bottom edge of triangle gives us the height; use 1/2(a+b)h to work out the area of the trapezium. 1/2(4+9)5 = 32.5' squared