Answer:
The density of the prism is 0.453 kilograms per cubic meter.
Step-by-step explanation:
Let suppose that mass in the prism is uniformly distributed. Then, the definition of density ([tex]\rho[/tex]), in kilograms per cubic meter, is defined by the equation below:
[tex]\rho = \frac{m}{V}[/tex] (1)
Where:
[tex]m[/tex] - Mass, in kilograms.
[tex]V[/tex] - Volume of the right angle triangle prism, in cubic meters.
Besides, the volume of the right angle triangle prism is:
[tex]V = \frac{1}{2}\cdot b\cdot h\cdot l[/tex] (2)
Where:
[tex]b[/tex] - Breadth of the base, in meters.
[tex]h[/tex] - Height of the base, in meters.
[tex]l[/tex] - Length of the base, in meters.
If we know that [tex]b = 2\,m[/tex], [tex]h = 2.5\,m[/tex], [tex]l = 3\,m[/tex] and [tex]m = 3.4\,kg[/tex], then the density of the prism is:
[tex]V = 7.5\,m^{3}[/tex]
[tex]\rho = 0.453\,\frac{kg}{m^{3}}[/tex]
The density of the prism is 0.453 kilograms per cubic meter.
