Question

Find the acceleration due to gravity on Titan's surface, given that its mass is 1.35 x 102kg and its radius is 2570 km

Answer 1

Answer:

1.36 x $10^{-15}$$ms^{-2}$

Explanation:

The equation $g = \frac{G*M}{R^2}$ would be used where:

g = acceleration due to gravity

G = universal gravitational constant (6.67408 × $10^{-11}$ $m^{3} kg^{-1} s^{-2}$)

M = mass

R = radius.

assuming the value following 10 is its exponent, which is a little confusing, the values given would simply be substituted.

Anyone can correct me if I'm wrong.