Question

Calculate the volume occupied by 2.00 moles of H₂ at 300.0 K and 1.25 atm

Answer 1

Answer:

V = 39.38 L

Explanation:

Given that,

No. of moles of H₂, n = 2

Temperature, T = 300 K

Pressure, P = 1.25 atm

We need to find the volume occupied by the gas. We can use the ideal gas law to find it such that,

$PV=nRT$

Where

R is gas constant, R = 0.08205 L-atm/mol-K

V is volume of the gas

Rearranging the above formula for V. So,

$V=\dfrac{nRT}{P}\\\\V=\dfrac{2\times 0.08205\times 300}{1.25}\\\\V=39.38\ L$

So, the volume occupied by the gas is 39.38 L.