Answer:
[tex](x,y) =(-4,-3)[/tex] --- Vertex
[tex]x = -4[/tex] --- Axis of symmetry
Step-by-step explanation:
Given
[tex]y = -6(x + 4)^2 - 3[/tex]
Solving (a): The vertex
For an equation written in
[tex]y = a(x - h)^2 + k[/tex]
The vertex is:
[tex](x,y) = (h,k)[/tex]
By comparison:
[tex]y = a(x - h)^2 + k[/tex] and [tex]y = -6(x + 4)^2 - 3[/tex]
[tex]-h =4[/tex] [tex]k = -3[/tex]
[tex]h =-4[/tex] [tex]k = -3[/tex]
So, the vertex is:
[tex](x,y) =(-4,-3)[/tex]
Solving (b): The axis of symmetry
For an equation written in
[tex]y = a(x - h)^2 + k[/tex]
The axis of symmetry is:
x = h
In (a):
[tex]h =-4[/tex]
So:
[tex]x = -4[/tex]
