Answer:
(5). [tex]\theta=36.86^{\circ}[/tex] (6) H = 25 units
Step-by-step explanation:
Given that,
Height of triangle, H = 15
Base, B = 20
(5)
We need to find the value of tanA.
[tex]\tan A=\dfrac{P}{B}\\\\\tan A=\dfrac{15}{20}\\\\A=\tan^{-1}(\dfrac{15}{20})\\\\A=36.86^{\circ}[/tex]
(6)
For a right angled triangle, Pythagoras theorem will be applicable as follows :
[tex]H^2=B^2+h^2\\\\H^2=20^2+15^2\\\\H=\sqrt{20^{2}+15^{2}}\\\\H=25\ \text{units}[/tex]
Hence, this is the required solution.
