Answer:
[tex](x,y) = (-2,-3)[/tex]
Step-by-step explanation:
Given
[tex]y = 3x + 3\\y =x-1[/tex]
Required
Solve by substitution
Substitute [tex]x-1[/tex] for [tex]y[/tex] in the first equation
[tex]y = 3x + 3[/tex]
[tex]x-1 = 3x + 3[/tex]
Collect like terms
[tex]x-3x =1+3[/tex]
[tex]-2x =4[/tex]
Solve for x
[tex]x = -2[/tex]
Substitute [tex]x = -2[/tex] in the second equation
[tex]y = x -1[/tex]
[tex]y = -2 -1[/tex]
[tex]y = -3[/tex]
So: the solution is:
[tex](x,y) = (-2,-3)[/tex]