Question

Calculate the volume occupied by 2.00 moles of H2 at 300.0 K and 1.25
atm

Answer 1

Answer:

V = 39.38 L

Explanation:

Given that,

No. of moles of H₂, n = 2

Temperature, T = 300 K

Pressure, P = 1.25 atm

We need to find the volume occupied by the gas. We can use the ideal gas law to find it such that,

$PV=nRT$

Where

R is gas constant, R = 0.08205 L-atm/mol-K

V is volume of the gas

Rearranging the above formula for V. So,

$V=\dfrac{nRT}{P}\\\\V=\dfrac{2\times 0.08205\times 300}{1.25}\\\\V=39.38\ L$

So, the volume occupied by the gas is 39.38 L.

Answer 2

The volume occupied by this hydrogen gas is equal to 39.408 Liters.

Given the following data:

• Temperature = 300 K

• Pressure = 1.25 atm.

• Ideal gas constant, R = 0.0821 L⋅atm/mol⋅K

• Number of moles = 2.00 moles.

To determine the volume occupied by this hydrogen gas, we would use the ideal gas law equation;

$V= \frac{nRT}{P}$

Where;

• P is the pressure.

• V is the volume.

• n is the number of moles of a gas.

• R is the ideal gas constant.

• T is the temperature.

Substituting the given parameters into the formula, we have;

$V=\frac{2 \times 0.0821 \times 300 }{1.25} \\\\V=\frac{49.26}{1.25}$

Volume, V = 39.408 Liters.

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