Question

A planet was discovered by the Kepler space telescope. The planet had a mass of8.0 x 10^27kg and a radius of 1.0 x 10^8m. What is the value of the acceleration due to gravity on the surface of the planet?

Answer 1

Answer:

$g=53.36\ m/s^2$

Explanation:

Given that,

The mass of the planet, $M=8\times 10^{27}\ kg$

The radius of the planet, $R=10^8\ m$

We need to find the value of the acceleration due to gravity on the surface of the planet. The formula for the acceleration due to gravity is given by :

$g=\dfrac{GM}{R^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 8\times 10^{27}}{(10^8)^2}\\\\g=53.36\ m/s^2$

So, the value of acceleration due to gravity on the surface of the plate is equal to $53.36\ m/s^2$.