Question

What are the [H+] and [OH-] for a substance with a pH of 9.2? Show work please

Answer 1

Explanation:

[H+]=10^-pH

[H+]=10^-9.2

[H+]=6.031x10^-10

[OH-]=1x10^-14÷[H+]

[OH-]=1x10^-14÷[6.031x10^-10]

[OH-]= 1.66x10^-5

im pretty sure this is right