From the indicated equation Zn +2 HCl → ZnCl2 + H2 if 7.56 moles of HCl are used with Zn, how many
moles of the product H2 ZnCl2 would be formed?
A) 15.12 mol
B) 5.20 mol
C) 58 mol
D) 3.78 mol

ACCESS MORE