Answer:
C
Step-by-step explanation:
The area is calculated as width × length , that is
[tex]\frac{50\sqrt{3} }{\sqrt{2} }[/tex] × [tex]\frac{80\sqrt{5} }{\sqrt{3} }[/tex] ( cancel [tex]\sqrt{3}[/tex] on numerator/ denominator
= [tex]\frac{50}{\sqrt{2} }[/tex] × 80[tex]\sqrt{5}[/tex]
= [tex]\frac{4000\sqrt{5} }{\sqrt{2} }[/tex]
To rationalise the denominator multiply numerator/denominator by [tex]\sqrt{2}[/tex]
= [tex]\frac{4000\sqrt{6} }{\sqrt{2} }[/tex] × [tex]\frac{\sqrt{2} }{\sqrt{2} }[/tex]
= [tex]\frac{4000\sqrt{10} }{2}[/tex]
= 2000[tex]\sqrt{10}[/tex] → C
